What is the power dissipated by a 10Ω resistor carrying a current of 3A?

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Question: What is the power dissipated by a 10Ω resistor carrying a current of 3A?

Options:

Correct Answer: 60W

Solution:

Power (P) is given by P = I^2 * R = (3A)^2 * 10Ω = 90W.

What is the power dissipated by a 10Ω resistor carrying a current of 3A?

What is the power dissipated by a 10Ω resistor carrying a current of 3A?

Step 1: Identify the values given in the problem. We have a resistor with a resistance (R) of 10 ohms (Ω) and a current (I) of 3 amperes (A).
Step 2: Recall the formula for power (P) in a resistor, which is P = I^2 * R.
Step 3: Substitute the current (I) into the formula. Here, I = 3A, so we calculate (3A)^2.
Step 4: Calculate (3A)^2, which is 3 * 3 = 9. So, (3A)^2 = 9A^2.
Step 5: Now, substitute this value back into the power formula: P = 9A^2 * 10Ω.
Step 6: Multiply 9 by 10 to find the power: 9 * 10 = 90.
Step 7: Therefore, the power dissipated by the resistor is 90 watts (W).

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