In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is
Practice Questions
Q1
In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the voltage drop across the 8Ω resistor?
4V
6V
8V
12V
Questions & Step-by-Step Solutions
In a circuit with a 12V battery and two resistors in series (4Ω and 8Ω), what is the voltage drop across the 8Ω resistor?
Step 1: Identify the total resistance in the circuit. Add the resistance values of the two resistors: 4Ω + 8Ω = 12Ω.
Step 2: Use Ohm's Law to find the current in the circuit. The formula is I = V / R, where V is the voltage of the battery (12V) and R is the total resistance (12Ω). So, I = 12V / 12Ω = 1A.
Step 3: Calculate the voltage drop across the 8Ω resistor using Ohm's Law again. The formula is Voltage drop = I * R, where I is the current (1A) and R is the resistance of the 8Ω resistor. So, Voltage drop = 1A * 8Ω = 8V.
