What is the charge stored in a capacitor of 5 µF at a voltage of 10 V?

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Question: What is the charge stored in a capacitor of 5 µF at a voltage of 10 V?

Options:

Correct Answer: 50 µC

Solution:

Charge Q = C * V = 5 x 10^-6 F * 10 V = 50 µC.

What is the charge stored in a capacitor of 5 µF at a voltage of 10 V?

What is the charge stored in a capacitor of 5 µF at a voltage of 10 V?

Step 1: Identify the values given in the problem. We have a capacitor with a capacitance (C) of 5 microfarads (µF) and a voltage (V) of 10 volts (V).
Step 2: Convert the capacitance from microfarads to farads. 5 µF is equal to 5 x 10^-6 F.
Step 3: Use the formula for charge stored in a capacitor, which is Q = C * V.
Step 4: Substitute the values into the formula: Q = (5 x 10^-6 F) * (10 V).
Step 5: Calculate the charge: Q = 5 x 10^-6 * 10 = 50 x 10^-6 C.
Step 6: Convert the charge from coulombs to microcoulombs. 50 x 10^-6 C is equal to 50 µC.

Capacitance – Capacitance is the ability of a capacitor to store charge per unit voltage, calculated using the formula Q = C * V.
Units of Measurement – Understanding the conversion between microfarads (µF), volts (V), and coulombs (C) is essential for accurate calculations.