What is the electric field strength at a distance of 2 m from a +5 µC point char
Practice Questions
Q1
What is the electric field strength at a distance of 2 m from a +5 µC point charge?
1.125 N/C
2.25 N/C
0.5625 N/C
0.75 N/C
Questions & Step-by-Step Solutions
What is the electric field strength at a distance of 2 m from a +5 µC point charge?
Step 1: Identify the formula for electric field strength (E) created by a point charge: E = k * |q| / r^2.
Step 2: Determine the values needed for the formula: k (Coulomb's constant) = 8.99 x 10^9 N m²/C², q (the charge) = +5 µC = 5 x 10^-6 C, and r (the distance) = 2 m.
Step 3: Substitute the values into the formula: E = (8.99 x 10^9 N m²/C²) * |5 x 10^-6 C| / (2 m)^2.
Step 4: Calculate (2 m)^2, which is 4 m².
Step 5: Now calculate E: E = (8.99 x 10^9 N m²/C²) * (5 x 10^-6 C) / 4 m².
Step 6: Multiply 8.99 x 10^9 by 5 x 10^-6 to get 44.95 x 10^3 N/C.
Step 7: Divide 44.95 x 10^3 N/C by 4 to get 11.2375 x 10^3 N/C.
Step 8: Convert 11.2375 x 10^3 N/C to standard form: 1.125 N/C.
