What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?

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Question: What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?

Options:

Correct Answer: 1.5 µF

Solution:

1/Ceq = 1/C1 + 1/C2 = 1/3 + 1/6 = 1/2. Therefore, Ceq = 2 µF.

What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?

What is the equivalent capacitance of two capacitors (3 µF and 6 µF) in series?

Step 1: Identify the values of the capacitors. We have C1 = 3 µF and C2 = 6 µF.
Step 2: Use the formula for capacitors in series: 1/Ceq = 1/C1 + 1/C2.
Step 3: Substitute the values into the formula: 1/Ceq = 1/3 + 1/6.
Step 4: Find a common denominator to add the fractions. The common denominator for 3 and 6 is 6.
Step 5: Rewrite the fractions: 1/3 = 2/6 and 1/6 = 1/6.
Step 6: Add the fractions: 1/Ceq = 2/6 + 1/6 = 3/6.
Step 7: Simplify the result: 3/6 = 1/2.
Step 8: Take the reciprocal to find Ceq: Ceq = 2 µF.

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