What is the potential difference across a capacitor of 5 µF charged to 10 V?

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Question: What is the potential difference across a capacitor of 5 µF charged to 10 V?

Options:

Correct Answer: 5 V

Solution:

V = Q/C; Q = C * V = 5 µF * 10 V = 50 µC, thus the potential difference is 10 V.

What is the potential difference across a capacitor of 5 µF charged to 10 V?

What is the potential difference across a capacitor of 5 µF charged to 10 V?

Step 1: Identify the values given in the question. We have a capacitor with a capacitance of 5 microfarads (µF) and a voltage of 10 volts (V).
Step 2: Recall the formula for charge (Q) in a capacitor, which is Q = C * V, where C is capacitance and V is voltage.
Step 3: Convert the capacitance from microfarads to farads. 5 µF = 5 x 10^-6 F.
Step 4: Substitute the values into the formula: Q = (5 x 10^-6 F) * (10 V).
Step 5: Calculate the charge (Q). Q = 5 x 10^-6 * 10 = 50 x 10^-6 C = 50 µC.
Step 6: Understand that the potential difference across the capacitor is the same as the voltage it was charged to, which is 10 V.

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