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What is the capacitance of a parallel plate capacitor with an area of 0.01 m² an

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Question: What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of k=2?

Options:

  1. 5.5 µF
  2. 4.4 µF
  3. 2.2 µF
  4. 1.1 µF

Correct Answer: 4.4 µF

Solution: 

C = k * ε₀ * (A/d) = 2 * (8.85 x 10^-12 F/m) * (0.01 m² / 0.001 m) = 4.4 µF.

What is the capacitance of a parallel plate capacitor with an area of 0.01 m² an

Practice Questions

Q1
What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of k=2?
  1. 5.5 µF
  2. 4.4 µF
  3. 2.2 µF
  4. 1.1 µF

Questions & Step-by-Step Solutions

What is the capacitance of a parallel plate capacitor with an area of 0.01 m² and a separation of 0.001 m, filled with a dielectric of k=2?
  • Step 1: Identify the formula for the capacitance of a parallel plate capacitor: C = k * ε₀ * (A/d).
  • Step 2: Determine the values needed for the formula: Area (A) = 0.01 m², separation (d) = 0.001 m, dielectric constant (k) = 2, and ε₀ (the permittivity of free space) = 8.85 x 10^-12 F/m.
  • Step 3: Substitute the values into the formula: C = 2 * (8.85 x 10^-12 F/m) * (0.01 m² / 0.001 m).
  • Step 4: Calculate the area divided by the separation: 0.01 m² / 0.001 m = 10.
  • Step 5: Multiply the values: C = 2 * (8.85 x 10^-12 F/m) * 10.
  • Step 6: Calculate the final capacitance: C = 2 * 8.85 x 10^-11 F = 1.77 x 10^-10 F.
  • Step 7: Convert the capacitance to microfarads: 1.77 x 10^-10 F = 0.177 µF.
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