What is the force between two charges of +1 µC and +1 µC separated by 0.1 m?

₹0.0

Question: What is the force between two charges of +1 µC and +1 µC separated by 0.1 m?

Options:

Correct Answer: 0.18 N

Solution:

F = k * |q1 * q2| / r² = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C)² / (0.1 m)² = 0.09 N.

What is the force between two charges of +1 µC and +1 µC separated by 0.1 m?

What is the force between two charges of +1 µC and +1 µC separated by 0.1 m?

Step 1: Identify the values given in the problem. We have two charges, q1 = +1 µC and q2 = +1 µC, and the distance between them, r = 0.1 m.
Step 2: Convert the charges from microcoulombs (µC) to coulombs (C). 1 µC = 1 x 10^-6 C, so q1 = 1 x 10^-6 C and q2 = 1 x 10^-6 C.
Step 3: Use Coulomb's Law formula to find the force (F) between the charges. The formula is F = k * |q1 * q2| / r², where k = 8.99 x 10^9 N m²/C².
Step 4: Substitute the values into the formula: F = (8.99 x 10^9 N m²/C²) * (1 x 10^-6 C) * (1 x 10^-6 C) / (0.1 m)².
Step 5: Calculate the numerator: (1 x 10^-6 C) * (1 x 10^-6 C) = 1 x 10^-12 C².
Step 6: Calculate the denominator: (0.1 m)² = 0.01 m².
Step 7: Now substitute these results back into the formula: F = (8.99 x 10^9 N m²/C²) * (1 x 10^-12 C²) / (0.01 m²).
Step 8: Calculate the force: F = (8.99 x 10^9 * 1 x 10^-12) / 0.01 = 0.09 N.

No concepts available.