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What is the capacitance of a capacitor with a charge of 12 µC and a voltage of 6

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Question: What is the capacitance of a capacitor with a charge of 12 µC and a voltage of 6 V?

Options:

  1. 2 µF
  2. 4 µF
  3. 6 µF
  4. 8 µF

Correct Answer: 4 µF

Solution: 

C = Q/V = 12 x 10^-6 C / 6 V = 2 x 10^-6 F = 2 µF.

What is the capacitance of a capacitor with a charge of 12 µC and a voltage of 6

Practice Questions

Q1
What is the capacitance of a capacitor with a charge of 12 µC and a voltage of 6 V?
  1. 2 µF
  2. 4 µF
  3. 6 µF
  4. 8 µF

Questions & Step-by-Step Solutions

What is the capacitance of a capacitor with a charge of 12 µC and a voltage of 6 V?
  • Step 1: Identify the formula for capacitance, which is C = Q / V.
  • Step 2: Note the values given in the question: charge (Q) is 12 µC and voltage (V) is 6 V.
  • Step 3: Convert the charge from microcoulombs to coulombs: 12 µC = 12 x 10^-6 C.
  • Step 4: Substitute the values into the formula: C = (12 x 10^-6 C) / (6 V).
  • Step 5: Perform the division: C = 2 x 10^-6 F.
  • Step 6: Convert the capacitance back to microfarads: 2 x 10^-6 F = 2 µF.
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