Question: What is the equivalent resistance of three resistors of 4 Ω, 6 Ω, and 12 Ω in series?

Options:

1. 22 Ω
2. 18 Ω
3. 16 Ω
4. 12 Ω

Correct Answer: 22 Ω

Solution:

In series, R_eq = R1 + R2 + R3 = 4 Ω + 6 Ω + 12 Ω = 22 Ω.