A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
Practice Questions
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Q1
A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
20%
15%
25%
10%
Mass percent = (mass of solute / (mass of solute + mass of solvent)) × 100 = (50 g / (50 g + 250 g)) × 100 = 20%.
Questions & Step-by-step Solutions
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Q
Q: A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
Solution: Mass percent = (mass of solute / (mass of solute + mass of solvent)) × 100 = (50 g / (50 g + 250 g)) × 100 = 20%.
Steps: 7
Step 1: Identify the mass of the solute (glucose) which is 50 g.
Step 2: Identify the mass of the solvent (water) which is 250 g.
Step 3: Calculate the total mass of the solution by adding the mass of the solute and the mass of the solvent: 50 g + 250 g = 300 g.
Step 4: Use the mass percent formula: Mass percent = (mass of solute / total mass of solution) × 100.
Step 5: Substitute the values into the formula: Mass percent = (50 g / 300 g) × 100.
Step 6: Calculate the mass percent: (50 / 300) × 100 = 16.67%.
Step 7: Round the result to the nearest whole number if necessary, which gives approximately 17%.
