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A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water

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Question: A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)

Options:

  1. 20%
  2. 15%
  3. 25%
  4. 10%

Correct Answer: 20%

Solution: 

Mass percent = (mass of solute / (mass of solute + mass of solvent)) × 100 = (50 g / (50 g + 250 g)) × 100 = 20%.

A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water

Practice Questions

Q1
A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
  1. 20%
  2. 15%
  3. 25%
  4. 10%

Questions & Step-by-Step Solutions

A solution is prepared by dissolving 50 g of glucose (C6H12O6) in 250 g of water. What is the mass percent of glucose in the solution? (Molar mass of glucose = 180 g/mol)
Correct Answer: 20%
  • Step 1: Identify the mass of the solute (glucose) which is 50 g.
  • Step 2: Identify the mass of the solvent (water) which is 250 g.
  • Step 3: Calculate the total mass of the solution by adding the mass of the solute and the mass of the solvent: 50 g + 250 g = 300 g.
  • Step 4: Use the mass percent formula: Mass percent = (mass of solute / total mass of solution) × 100.
  • Step 5: Substitute the values into the formula: Mass percent = (50 g / 300 g) × 100.
  • Step 6: Calculate the mass percent: (50 / 300) × 100 = 16.67%.
  • Step 7: Round the result to the nearest whole number if necessary, which gives approximately 17%.
  • Mass Percent Calculation – This concept involves calculating the mass percent of a solute in a solution, which is determined by the formula: (mass of solute / total mass of solution) × 100.
  • Understanding Solute and Solvent – Recognizing the difference between solute (glucose) and solvent (water) is crucial for correctly applying the mass percent formula.
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