If 10 grams of NaOH is dissolved in enough water to make 500 mL of solution, what is the molarity of the solution? (Molar mass of NaOH = 40 g/mol)

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Q: If 10 grams of NaOH is dissolved in enough water to make 500 mL of solution, what is the molarity of the solution? (Molar mass of NaOH = 40 g/mol)

Solution: Moles of NaOH = 10 g / 40 g/mol = 0.25 moles. Molarity = 0.25 moles / 0.5 L = 0.5 M.

Steps: 7

Step 1: Identify the mass of NaOH you have, which is 10 grams.
Step 2: Find the molar mass of NaOH, which is given as 40 g/mol.
Step 3: Calculate the number of moles of NaOH using the formula: Moles = Mass (g) / Molar Mass (g/mol). So, Moles of NaOH = 10 g / 40 g/mol.
Step 4: Perform the calculation: 10 g / 40 g/mol = 0.25 moles of NaOH.
Step 5: Convert the volume of the solution from mL to L. Since 500 mL = 0.5 L.
Step 6: Calculate the molarity (M) using the formula: Molarity = Moles of solute / Volume of solution (L). So, Molarity = 0.25 moles / 0.5 L.
Step 7: Perform the calculation: 0.25 moles / 0.5 L = 0.5 M.