Question: If the coordinates of the vertices of a triangle are A(1, 1), B(4, 5), and C(7, 2), what is the perimeter of the triangle?
Options:
Correct Answer: 14
Solution:
Perimeter = AB + BC + CA = √((4-1)² + (5-1)²) + √((7-4)² + (2-5)²) + √((1-7)² + (1-2)²) = 3 + √(9 + 9) + √(36 + 1) = 3 + 4.24 + 6.08 = 13.32.