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What is the area of a triangle with vertices at (0, 0), (b, 0), and (0, h)?

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Question: What is the area of a triangle with vertices at (0, 0), (b, 0), and (0, h)?

Options:

  1. bh/2
  2. bh
  3. b+h
  4. b*h/2

Correct Answer: bh/2

Solution:

Area = 1/2 * base * height = 1/2 * b * h = bh/2.

What is the area of a triangle with vertices at (0, 0), (b, 0), and (0, h)?

Practice Questions

Q1
What is the area of a triangle with vertices at (0, 0), (b, 0), and (0, h)?
  1. bh/2
  2. bh
  3. b+h
  4. b*h/2

Questions & Step-by-Step Solutions

What is the area of a triangle with vertices at (0, 0), (b, 0), and (0, h)?
  • Step 1: Identify the vertices of the triangle. The vertices are (0, 0), (b, 0), and (0, h).
  • Step 2: Determine the base of the triangle. The base is the distance between the points (0, 0) and (b, 0), which is 'b'.
  • Step 3: Determine the height of the triangle. The height is the distance from the point (0, h) straight down to the base, which is 'h'.
  • Step 4: Use the formula for the area of a triangle. The formula is Area = 1/2 * base * height.
  • Step 5: Substitute the values of base and height into the formula. This gives us Area = 1/2 * b * h.
  • Step 6: Simplify the expression. The area can be written as Area = bh/2.
  • Area of a Triangle – The area of a triangle can be calculated using the formula Area = 1/2 * base * height, where the base and height are perpendicular to each other.
  • Coordinate Geometry – Understanding how to identify the base and height of a triangle given its vertices in a coordinate plane.
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