Question: If a triangle has vertices at (1, 2), (4, 6), and (7, 2), what is its perimeter?
Options:
Correct Answer: 18
Solution:
Calculate the lengths of the sides using the distance formula: AB = √((4-1)² + (6-2)²) = 5, BC = √((7-4)² + (2-6)²) = 5, CA = √((1-7)² + (2-2)²) = 6. Perimeter = 5 + 5 + 6 = 16.