Question: In triangle ABC, if angle A = 60 degrees, angle B = 70 degrees, and side a = 10 cm, what is the length of side b using the Law of Sines?
Options:
Correct Answer: 9.15 cm
Solution:
Using the Law of Sines: a/sin(A) = b/sin(B). Thus, b = a * (sin(B)/sin(A)) = 10 * (sin(70)/sin(60)). Calculating gives b β 10 * (0.9397/0.8660) β 10.80 cm.