What is the distance between the points (3, 4) and (7, 1) in the coordinate plan

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Question: What is the distance between the points (3, 4) and (7, 1) in the coordinate plane?

Options:

Correct Answer: 5

Solution:

Distance = √((7-3)² + (1-4)²) = √(4 + 9) = √13 ≈ 3.6.

What is the distance between the points (3, 4) and (7, 1) in the coordinate plane?

What is the distance between the points (3, 4) and (7, 1) in the coordinate plane?

Step 1: Identify the coordinates of the two points. The first point is (3, 4) and the second point is (7, 1).
Step 2: Use the distance formula, which is Distance = √((x2 - x1)² + (y2 - y1)²). Here, (x1, y1) is (3, 4) and (x2, y2) is (7, 1).
Step 3: Calculate (x2 - x1). This is 7 - 3 = 4.
Step 4: Calculate (y2 - y1). This is 1 - 4 = -3.
Step 5: Square the results from Step 3 and Step 4. So, (4)² = 16 and (-3)² = 9.
Step 6: Add the squared results together. This is 16 + 9 = 25.
Step 7: Take the square root of the sum from Step 6. √25 = 5.
Step 8: The distance between the points (3, 4) and (7, 1) is 5.

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