What is the equation of a line parallel to y = -3x + 2 that passes through the p
Practice Questions
Q1
What is the equation of a line parallel to y = -3x + 2 that passes through the point (1, 4)?
y = -3x + 7
y = 3x + 1
y = -3x + 1
y = 3x - 1
Questions & Step-by-Step Solutions
What is the equation of a line parallel to y = -3x + 2 that passes through the point (1, 4)?
Step 1: Identify the slope of the given line y = -3x + 2. The slope is -3.
Step 2: Since parallel lines have the same slope, the slope of our new line will also be -3.
Step 3: Use the point-slope form of a line equation, which is y - y1 = m(x - x1), where (x1, y1) is the point the line passes through and m is the slope.
Step 4: Substitute the point (1, 4) into the point-slope form. Here, x1 = 1, y1 = 4, and m = -3.
Step 5: The equation becomes y - 4 = -3(x - 1).
Step 6: Simplify the equation. Distribute -3: y - 4 = -3x + 3.
Step 7: Add 4 to both sides to isolate y: y = -3x + 3 + 4.
