What is the molality of a solution prepared by dissolving 5 moles of NaCl in 2 k

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Question: What is the molality of a solution prepared by dissolving 5 moles of NaCl in 2 kg of water?

Options:

Correct Answer: 2.5 mol/kg

Solution:

Molality (m) = moles of solute / mass of solvent (kg) = 5 moles / 2 kg = 2.5 mol/kg.

What is the molality of a solution prepared by dissolving 5 moles of NaCl in 2 kg of water?

What is the molality of a solution prepared by dissolving 5 moles of NaCl in 2 kg of water?

Correct Answer: 2.5 mol/kg

Step 1: Identify the number of moles of the solute (NaCl). In this case, it is 5 moles.
Step 2: Identify the mass of the solvent (water) in kilograms. Here, it is 2 kg.
Step 3: Use the formula for molality, which is molality (m) = moles of solute / mass of solvent (kg).
Step 4: Plug in the values into the formula: m = 5 moles / 2 kg.
Step 5: Calculate the result: 5 divided by 2 equals 2.5.
Step 6: State the final answer: The molality of the solution is 2.5 mol/kg.

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