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How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar ma

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Question: How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar mass of KCl = 74.5 g/mol)

Options:

  1. 37.25 g
  2. 74.5 g
  3. 148.5 g
  4. 18.5 g

Correct Answer: 37.25 g

Solution: 

To find the mass, use the formula: mass = moles x molar mass. Thus, 0.5 moles x 74.5 g/mol = 37.25 g.

How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar ma

Practice Questions

Q1
How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar mass of KCl = 74.5 g/mol)
  1. 37.25 g
  2. 74.5 g
  3. 148.5 g
  4. 18.5 g

Questions & Step-by-Step Solutions

How many grams of KCl are needed to prepare 0.5 moles of KCl solution? (Molar mass of KCl = 74.5 g/mol)
  • Step 1: Identify the number of moles of KCl you need, which is 0.5 moles.
  • Step 2: Find the molar mass of KCl, which is given as 74.5 g/mol.
  • Step 3: Use the formula to calculate mass: mass = moles x molar mass.
  • Step 4: Substitute the values into the formula: mass = 0.5 moles x 74.5 g/mol.
  • Step 5: Calculate the result: 0.5 x 74.5 = 37.25 grams.
  • Molar Mass Calculation – Understanding how to calculate the mass of a substance using its moles and molar mass.
  • Stoichiometry – Applying stoichiometric principles to convert between moles and grams.
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