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What is the mass of 0.5 moles of CaCO3?
What is the mass of 0.5 moles of CaCO3?
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Practice Questions
1 question
Q1
What is the mass of 0.5 moles of CaCO3?
50 g
25 g
100 g
75 g
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Molar mass of CaCO3 = 40 + 12 + 16*3 = 100 g/mol. Mass = moles x molar mass = 0.5 moles x 100 g/mol = 50 g.
Questions & Step-by-step Solutions
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Q
Q: What is the mass of 0.5 moles of CaCO3?
Solution:
Molar mass of CaCO3 = 40 + 12 + 16*3 = 100 g/mol. Mass = moles x molar mass = 0.5 moles x 100 g/mol = 50 g.
Steps: 10
Show Steps
Step 1: Identify the chemical formula of calcium carbonate, which is CaCO3.
Step 2: Calculate the molar mass of CaCO3 by adding the atomic masses of its elements: calcium (Ca), carbon (C), and oxygen (O).
Step 3: Find the atomic mass of calcium (Ca), which is approximately 40 g/mol.
Step 4: Find the atomic mass of carbon (C), which is approximately 12 g/mol.
Step 5: Find the atomic mass of oxygen (O), which is approximately 16 g/mol.
Step 6: Since there are three oxygen atoms in CaCO3, calculate the total mass of oxygen: 16 g/mol * 3 = 48 g/mol.
Step 7: Add the atomic masses together: 40 g/mol (Ca) + 12 g/mol (C) + 48 g/mol (O) = 100 g/mol.
Step 8: Use the formula for mass: Mass = moles x molar mass.
Step 9: Substitute the values: Mass = 0.5 moles x 100 g/mol.
Step 10: Calculate the mass: 0.5 x 100 = 50 g.
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