Question: In a group of 50 people, 30 like tea, 20 like coffee, and 10 like both. What is the probability that a person chosen at random likes either tea or coffee?
Options:
Correct Answer: 4/5
Solution:
Using the principle of inclusion-exclusion, P(Tea or Coffee) = P(Tea) + P(Coffee) - P(Both) = (30/50) + (20/50) - (10/50) = 40/50 = 4/5.