A 2 kg piece of copper (specific heat = 0.385 J/g°C) is heated from 25°C to 75°C

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Question: A 2 kg piece of copper (specific heat = 0.385 J/g°C) is heated from 25°C to 75°C. How much heat is absorbed? (2022)

Options:

Correct Answer: 3000 J

Exam Year: 2022

Solution:

Q = mcΔT = 2000 g * 0.385 J/g°C * (75°C - 25°C) = 38500 J.

A 2 kg piece of copper (specific heat = 0.385 J/g°C) is heated from 25°C to 75°C. How much heat is absorbed? (2022)

A 2 kg piece of copper (specific heat = 0.385 J/g°C) is heated from 25°C to 75°C. How much heat is absorbed? (2022)

Step 1: Identify the mass of the copper piece. It is given as 2 kg. Convert this to grams because the specific heat is in J/g°C. 2 kg = 2000 g.
Step 2: Identify the specific heat of copper. It is given as 0.385 J/g°C.
Step 3: Determine the initial temperature (T1) and final temperature (T2). T1 is 25°C and T2 is 75°C.
Step 4: Calculate the change in temperature (ΔT) using the formula ΔT = T2 - T1. So, ΔT = 75°C - 25°C = 50°C.
Step 5: Use the formula for heat absorbed (Q): Q = mcΔT. Substitute the values: Q = 2000 g * 0.385 J/g°C * 50°C.
Step 6: Perform the multiplication: Q = 2000 * 0.385 * 50 = 38500 J.

Specific Heat Capacity – The amount of heat required to raise the temperature of a unit mass of a substance by one degree Celsius.
Heat Transfer Calculation – Using the formula Q = mcΔT to calculate the heat absorbed or released during a temperature change.