What is the value of P(1) for the polynomial P(x) = 2x^2 + 3x - 5?

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Question: What is the value of P(1) for the polynomial P(x) = 2x^2 + 3x - 5?

Options:

Correct Answer: 1

Solution:

Substituting x = 1 into P(x) gives P(1) = 2(1)^2 + 3(1) - 5 = 0.

What is the value of P(1) for the polynomial P(x) = 2x^2 + 3x - 5?

What is the value of P(1) for the polynomial P(x) = 2x^2 + 3x - 5?

Step 1: Identify the polynomial P(x) = 2x^2 + 3x - 5.
Step 2: Substitute x = 1 into the polynomial. This means we replace every x in P(x) with 1.
Step 3: Calculate P(1) by performing the operations: P(1) = 2(1)^2 + 3(1) - 5.
Step 4: Calculate (1)^2, which is 1.
Step 5: Multiply 2 by 1 to get 2.
Step 6: Calculate 3(1), which is 3.
Step 7: Now combine the results: P(1) = 2 + 3 - 5.
Step 8: Add 2 and 3 to get 5.
Step 9: Subtract 5 from 5 to get 0.
Step 10: Therefore, the value of P(1) is 0.

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