In a dihybrid cross between two heterozygous parents (AaBb x AaBb), what fractio

In a dihybrid cross between two heterozygous parents (AaBb x AaBb), what fraction of the offspring will be homozygous recessive for both traits?

In a dihybrid cross between two heterozygous parents (AaBb x AaBb), what fraction of the offspring will be homozygous recessive for both traits?

Step 1: Understand the parents' genotypes. Both parents are heterozygous for two traits, which means they have the genotype AaBb.
Step 2: Identify the possible gametes each parent can produce. Each parent can produce four types of gametes: AB, Ab, aB, and ab.
Step 3: Set up a Punnett square. Create a 4x4 grid to represent the combinations of the gametes from both parents.
Step 4: Fill in the Punnett square. Combine the gametes from each parent to fill in the squares. You will get 16 combinations in total.
Step 5: Identify the homozygous recessive genotype. The homozygous recessive genotype for both traits is aabb.
Step 6: Count the occurrences of aabb in the Punnett square. There is only 1 combination that results in aabb.
Step 7: Calculate the fraction. Since there are 16 total combinations and only 1 is aabb, the fraction is 1/16.

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