If the ratio of the ages of A and B is 4:5 and A is 20 years old, how old is B?

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Question: If the ratio of the ages of A and B is 4:5 and A is 20 years old, how old is B?

Options:

Correct Answer: 25

Solution:

If A\'s age is 4x and B\'s age is 5x, then 4x = 20 => x = 5. Therefore, B\'s age = 5x = 25.

If the ratio of the ages of A and B is 4:5 and A is 20 years old, how old is B?

If the ratio of the ages of A and B is 4:5 and A is 20 years old, how old is B?

Step 1: Understand the ratio of ages. The ratio of A's age to B's age is 4:5.
Step 2: Represent A's age as 4x and B's age as 5x, where x is a common multiplier.
Step 3: Since we know A's age is 20 years, we can set up the equation: 4x = 20.
Step 4: Solve for x by dividing both sides of the equation by 4: x = 20 / 4.
Step 5: Calculate x, which gives us x = 5.
Step 6: Now, find B's age by substituting x back into the expression for B's age: B's age = 5x.
Step 7: Calculate B's age: B's age = 5 * 5 = 25.

Ratio and Proportion – Understanding and applying the concept of ratios to determine relative ages.
Algebraic Manipulation – Using algebra to solve for unknowns based on given relationships.