What is the wind chill factor at a temperature of -5°C with a wind speed of 20 k

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Question: What is the wind chill factor at a temperature of -5°C with a wind speed of 20 km/h? (2020)

Options:

Correct Answer: -15°C

Exam Year: 2020

Solution:

Using the wind chill formula, Wind Chill = 13.12 + 0.6215*T - 11.37*(V^0.16) + 0.3965*T*(V^0.16), we find it to be approximately -15°C.

What is the wind chill factor at a temperature of -5°C with a wind speed of 20 km/h? (2020)

What is the wind chill factor at a temperature of -5°C with a wind speed of 20 km/h? (2020)

Step 1: Identify the temperature (T) and wind speed (V). Here, T = -5°C and V = 20 km/h.
Step 2: Convert the wind speed from km/h to m/s if necessary, but in this case, we can use it directly in the formula.
Step 3: Plug the values into the wind chill formula: Wind Chill = 13.12 + 0.6215*(-5) - 11.37*(20^0.16) + 0.3965*(-5)*(20^0.16).
Step 4: Calculate each part of the formula: First, calculate 0.6215 * (-5) = -3.1075.
Step 5: Calculate 20^0.16, which is approximately 1.724.
Step 6: Now calculate -11.37 * 1.724 = -19.59888.
Step 7: Calculate 0.3965 * (-5) * 1.724 = -3.4195.
Step 8: Add all the parts together: 13.12 - 3.1075 - 19.59888 - 3.4195.
Step 9: The total is approximately -15°C.

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