A mixture of two liquids A and B is in the ratio 3:2. If the total volume of the

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Question: A mixture of two liquids A and B is in the ratio 3:2. If the total volume of the mixture is 50 liters, how much liquid A is there?

Options:

Correct Answer: 30 liters

Solution:

Let the volumes of A and B be 3x and 2x respectively. Then, 3x + 2x = 50 liters. 5x = 50, x = 10. Therefore, volume of A = 3x = 30 liters.

A mixture of two liquids A and B is in the ratio 3:2. If the total volume of the mixture is 50 liters, how much liquid A is there?

A mixture of two liquids A and B is in the ratio 3:2. If the total volume of the mixture is 50 liters, how much liquid A is there?

Step 1: Understand that the mixture of liquids A and B is in the ratio 3:2.
Step 2: This means for every 3 parts of liquid A, there are 2 parts of liquid B.
Step 3: Let 'x' be a common multiplier. Then, the volume of liquid A can be represented as 3x and the volume of liquid B as 2x.
Step 4: Add the volumes of A and B together: 3x + 2x.
Step 5: This simplifies to 5x. So, we have 5x = 50 liters (the total volume of the mixture).
Step 6: To find 'x', divide both sides of the equation by 5: x = 50 / 5.
Step 7: Calculate x, which equals 10.
Step 8: Now, find the volume of liquid A by multiplying 3 by x: Volume of A = 3x = 3 * 10.
Step 9: Calculate the volume of A, which equals 30 liters.

Ratios and Proportions – Understanding how to express quantities in a given ratio and solve for unknowns using algebra.
Algebraic Equations – Setting up and solving linear equations based on the relationships between quantities.