A mixture contains 30% alcohol and 70% water. If 10 liters of the mixture is tak

A mixture contains 30% alcohol and 70% water. If 10 liters of the mixture is taken out, how much alcohol is left in the mixture?

A mixture contains 30% alcohol and 70% water. If 10 liters of the mixture is taken out, how much alcohol is left in the mixture?

Step 1: Understand that the mixture is made up of 30% alcohol and 70% water.
Step 2: Know that you are taking out 10 liters of this mixture.
Step 3: Calculate how much alcohol is in the 10 liters taken out. Since the mixture is 30% alcohol, you find 30% of 10 liters.
Step 4: Calculate 30% of 10 liters: 30% of 10 = 0.30 * 10 = 3 liters of alcohol.
Step 5: Now, determine how much alcohol was originally in the mixture. Since the original mixture was 10 liters, it also contained 3 liters of alcohol.
Step 6: After removing 3 liters of alcohol, calculate how much alcohol is left in the mixture. The original amount of alcohol was 3 liters, and you removed 3 liters.
Step 7: Subtract the removed alcohol from the original amount: 3 liters - 3 liters = 0 liters of alcohol left.

Percentage Calculation – Understanding how to calculate percentages of a mixture and apply them to find the amount of a component.
Volume Reduction – Recognizing how the removal of a portion of a mixture affects the total volume and the remaining quantities of its components.