Question: A mixture contains 30% alcohol and 70% water. If 10 liters of the mixture is taken out, how much alcohol is left in the mixture?
Options:
Correct Answer: 5 liters
Solution:
In 10 liters of the mixture, alcohol = 30% of 10 = 3 liters. If the original mixture was 10 liters, the remaining alcohol = 30% of (original volume - 10) = 30% of (10 - 10) = 0 liters. Thus, 3 liters of alcohol is removed, leaving 0 liters.
