What is the equation of the line that is perpendicular to y = 3x + 4 and passes
Practice Questions
Q1
What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the point (1, 1)? (2022)
y - 1 = -1/3(x - 1)
y - 1 = 3(x - 1)
y - 1 = 3/1(x - 1)
y - 1 = -3(x - 1)
Questions & Step-by-Step Solutions
What is the equation of the line that is perpendicular to y = 3x + 4 and passes through the point (1, 1)? (2022)
Step 1: Identify the slope of the given line y = 3x + 4. The slope (m) is 3.
Step 2: Find the slope of the line that is perpendicular to the given line. The slope of a perpendicular line is the negative reciprocal of the original slope. So, the negative reciprocal of 3 is -1/3.
Step 3: Use the point-slope form of a line equation, which is y - y1 = m(x - x1), where (x1, y1) is the point the line passes through. Here, (x1, y1) is (1, 1) and m is -1/3.
Step 4: Substitute the values into the point-slope form: y - 1 = -1/3(x - 1).
Step 5: This is the equation of the line that is perpendicular to y = 3x + 4 and passes through the point (1, 1).
