What is the value of the polynomial P(x) = 4x^2 - 3x + 7 when x = 2?

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Question: What is the value of the polynomial P(x) = 4x^2 - 3x + 7 when x = 2?

Options:

Correct Answer: 27

Solution:

Substituting x = 2 into the polynomial gives P(2) = 4(2^2) - 3(2) + 7 = 16 - 6 + 7 = 27.

What is the value of the polynomial P(x) = 4x^2 - 3x + 7 when x = 2?

What is the value of the polynomial P(x) = 4x^2 - 3x + 7 when x = 2?

Step 1: Identify the polynomial P(x) = 4x^2 - 3x + 7.
Step 2: Substitute x = 2 into the polynomial. This means replacing every x in the polynomial with 2.
Step 3: Calculate 2^2, which is 4.
Step 4: Multiply 4 by 4 (from 4x^2), which gives 16.
Step 5: Multiply -3 by 2 (from -3x), which gives -6.
Step 6: Now, add the results together: 16 (from 4x^2) - 6 (from -3x) + 7.
Step 7: First, calculate 16 - 6, which equals 10.
Step 8: Finally, add 10 + 7, which equals 17.

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