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A jar contains 5 green, 3 yellow, and 2 blue marbles. If one marble is drawn at

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Question: A jar contains 5 green, 3 yellow, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?

Options:

  1. 1/2
  2. 2/5
  3. 4/5
  4. 3/5

Correct Answer: 3/5

Solution: 

Total marbles = 5 + 3 + 2 = 10. Green or yellow = 5 + 3 = 8. Probability = (Green + Yellow) / Total = 8/10 = 4/5.

A jar contains 5 green, 3 yellow, and 2 blue marbles. If one marble is drawn at

Practice Questions

Q1
A jar contains 5 green, 3 yellow, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
  1. 1/2
  2. 2/5
  3. 4/5
  4. 3/5

Questions & Step-by-Step Solutions

A jar contains 5 green, 3 yellow, and 2 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
  • Step 1: Count the number of green marbles in the jar. There are 5 green marbles.
  • Step 2: Count the number of yellow marbles in the jar. There are 3 yellow marbles.
  • Step 3: Count the number of blue marbles in the jar. There are 2 blue marbles.
  • Step 4: Add the total number of marbles together: 5 (green) + 3 (yellow) + 2 (blue) = 10 total marbles.
  • Step 5: Add the number of green and yellow marbles together: 5 (green) + 3 (yellow) = 8 marbles that are either green or yellow.
  • Step 6: To find the probability of drawing a green or yellow marble, divide the number of green or yellow marbles by the total number of marbles: 8 (green or yellow) / 10 (total) = 4/5.
  • Step 7: The final answer is that the probability of drawing a green or yellow marble is 4/5.
  • Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
  • Counting Outcomes – Understanding how to count the total number of outcomes and favorable outcomes in a probability scenario.
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