A bag contains 4 white, 5 black, and 6 red balls. If one ball is drawn at random

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Question: A bag contains 4 white, 5 black, and 6 red balls. If one ball is drawn at random, what is the probability that it is not black?

Options:

Correct Answer: 7/11

Solution:

Total balls = 4 + 5 + 6 = 15. Non-black balls = 4 + 6 = 10. Probability = Non-black balls / Total balls = 10/15 = 2/3.

A bag contains 4 white, 5 black, and 6 red balls. If one ball is drawn at random, what is the probability that it is not black?

A bag contains 4 white, 5 black, and 6 red balls. If one ball is drawn at random, what is the probability that it is not black?

Step 1: Count the total number of balls in the bag. There are 4 white, 5 black, and 6 red balls.
Step 2: Add the number of balls together: 4 (white) + 5 (black) + 6 (red) = 15 total balls.
Step 3: Count the number of non-black balls. Non-black balls are the white and red balls: 4 (white) + 6 (red) = 10 non-black balls.
Step 4: To find the probability of drawing a non-black ball, divide the number of non-black balls by the total number of balls: 10 (non-black) / 15 (total) = 10/15.
Step 5: Simplify the fraction 10/15 to its simplest form: 10/15 = 2/3.

Probability Calculation – Understanding how to calculate the probability of an event by determining the ratio of favorable outcomes to total outcomes.
Complementary Events – Recognizing that the probability of an event not occurring can be calculated by subtracting the probability of the event occurring from 1.