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For the equation x^2 + 4x + k = 0 to have real roots, what must be the condition
Practice Questions
Q1
For the equation x^2 + 4x + k = 0 to have real roots, what must be the condition on k? (2023)
k >= 0
k <= 0
k >= 16
k <= 16
Questions & Step-by-Step Solutions
For the equation x^2 + 4x + k = 0 to have real roots, what must be the condition on k? (2023)
Steps
Concepts
Step 1: Identify the equation given, which is x^2 + 4x + k = 0.
Step 2: Recognize that for a quadratic equation to have real roots, the discriminant must be non-negative.
Step 3: The discriminant (D) for the equation ax^2 + bx + c = 0 is given by the formula D = b^2 - 4ac.
Step 4: In our equation, a = 1, b = 4, and c = k.
Step 5: Substitute the values into the discriminant formula: D = 4^2 - 4*1*k.
Step 6: Calculate 4^2, which is 16, so we have D = 16 - 4k.
Step 7: Set the discriminant greater than or equal to zero for real roots: 16 - 4k >= 0.
Step 8: Rearrange the inequality to isolate k: 16 >= 4k.
Step 9: Divide both sides by 4: 4 >= k.
Step 10: Rewrite the condition: k must be less than or equal to 4.
Discriminant
– The discriminant of a quadratic equation determines the nature of its roots; for real roots, it must be non-negative.
Quadratic Equation
– Understanding the standard form of a quadratic equation and how to manipulate it to find conditions on coefficients.
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