For the equation x^2 + 4x + k = 0 to have real roots, what must be the condition

Practice Questions

Q1
For the equation x^2 + 4x + k = 0 to have real roots, what must be the condition on k? (2023)
  1. k >= 0
  2. k <= 0
  3. k >= 16
  4. k <= 16

Questions & Step-by-Step Solutions

For the equation x^2 + 4x + k = 0 to have real roots, what must be the condition on k? (2023)
  • Step 1: Identify the equation given, which is x^2 + 4x + k = 0.
  • Step 2: Recognize that for a quadratic equation to have real roots, the discriminant must be non-negative.
  • Step 3: The discriminant (D) for the equation ax^2 + bx + c = 0 is given by the formula D = b^2 - 4ac.
  • Step 4: In our equation, a = 1, b = 4, and c = k.
  • Step 5: Substitute the values into the discriminant formula: D = 4^2 - 4*1*k.
  • Step 6: Calculate 4^2, which is 16, so we have D = 16 - 4k.
  • Step 7: Set the discriminant greater than or equal to zero for real roots: 16 - 4k >= 0.
  • Step 8: Rearrange the inequality to isolate k: 16 >= 4k.
  • Step 9: Divide both sides by 4: 4 >= k.
  • Step 10: Rewrite the condition: k must be less than or equal to 4.
  • Discriminant – The discriminant of a quadratic equation determines the nature of its roots; for real roots, it must be non-negative.
  • Quadratic Equation – Understanding the standard form of a quadratic equation and how to manipulate it to find conditions on coefficients.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely