If a 10 kg object is lifted to a height of 5 m, what is the work done against gr

If a 10 kg object is lifted to a height of 5 m, what is the work done against gravity? (Use g = 9.8 m/s²) (2021)

If a 10 kg object is lifted to a height of 5 m, what is the work done against gravity? (Use g = 9.8 m/s²) (2021)

Step 1: Identify the mass of the object. In this case, the mass (m) is 10 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. We are given g = 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = mgh.
Step 5: Substitute the values into the formula: Work = 10 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 10 × 9.8 = 98, then 98 × 5 = 490.
Step 7: Conclude that the work done against gravity is 490 Joules (J).

Work Done Against Gravity – The work done against gravity is calculated using the formula W = mgh, where W is work, m is mass, g is acceleration due to gravity, and h is height.