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What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?
What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?
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Q1
What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?
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In UF6, Uranium is in the +6 oxidation state as it forms six bonds with fluorine.
Questions & Step-by-step Solutions
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Q
Q: What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?
Solution:
In UF6, Uranium is in the +6 oxidation state as it forms six bonds with fluorine.
Steps: 7
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Step 1: Identify the chemical formula of the compound, which is UF6.
Step 2: Recognize that UF6 consists of one Uranium (U) atom and six Fluorine (F) atoms.
Step 3: Know that Fluorine typically has an oxidation state of -1.
Step 4: Calculate the total oxidation state contributed by the six Fluorine atoms: 6 F atoms × -1 = -6.
Step 5: Set up the equation for the overall charge of the compound: Oxidation state of U + Total oxidation state of F = 0.
Step 6: Substitute the known values into the equation: Oxidation state of U - 6 = 0.
Step 7: Solve for the oxidation state of Uranium: Oxidation state of U = +6.
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