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What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?

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Question: What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?

Options:

  1. +4
  2. +6
  3. +5
  4. 0

Correct Answer: +6

Solution: 

In UF6, Uranium is in the +6 oxidation state as it forms six bonds with fluorine.

What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?

Practice Questions

Q1
What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?
  1. +4
  2. +6
  3. +5
  4. 0

Questions & Step-by-Step Solutions

What is the oxidation state of Uranium in Uranium Hexafluoride (UF6)?
Correct Answer: +6
  • Step 1: Identify the chemical formula of the compound, which is UF6.
  • Step 2: Recognize that UF6 consists of one Uranium (U) atom and six Fluorine (F) atoms.
  • Step 3: Know that Fluorine typically has an oxidation state of -1.
  • Step 4: Calculate the total oxidation state contributed by the six Fluorine atoms: 6 F atoms × -1 = -6.
  • Step 5: Set up the equation for the overall charge of the compound: Oxidation state of U + Total oxidation state of F = 0.
  • Step 6: Substitute the known values into the equation: Oxidation state of U - 6 = 0.
  • Step 7: Solve for the oxidation state of Uranium: Oxidation state of U = +6.
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