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A box contains 5 red balls, 3 blue balls, and 2 green balls. If one ball is draw

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Question: A box contains 5 red balls, 3 blue balls, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue? (2023)

Options:

  1. 0.5
  2. 0.6
  3. 0.7
  4. 0.8

Correct Answer: 0.7

Exam Year: 2023

Solution: 

Total balls = 10. Non-blue balls = 5 + 2 = 7. Probability = Non-blue balls / Total balls = 7/10 = 0.7.

A box contains 5 red balls, 3 blue balls, and 2 green balls. If one ball is draw

Practice Questions

Q1
A box contains 5 red balls, 3 blue balls, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue? (2023)
  1. 0.5
  2. 0.6
  3. 0.7
  4. 0.8

Questions & Step-by-Step Solutions

A box contains 5 red balls, 3 blue balls, and 2 green balls. If one ball is drawn at random, what is the probability that it is not blue? (2023)
  • Step 1: Count the total number of balls in the box. There are 5 red balls, 3 blue balls, and 2 green balls.
  • Step 2: Add the number of red, blue, and green balls together to find the total: 5 + 3 + 2 = 10.
  • Step 3: Identify the number of non-blue balls. Non-blue balls are red and green: 5 red + 2 green = 7.
  • Step 4: Calculate the probability of drawing a non-blue ball. Use the formula: Probability = (Number of non-blue balls) / (Total number of balls).
  • Step 5: Substitute the numbers into the formula: Probability = 7 / 10.
  • Step 6: Convert the fraction to a decimal if needed: 7 / 10 = 0.7.
  • Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to total outcomes.
  • Counting Outcomes – Understanding how to count the total number of outcomes and favorable outcomes in a probability scenario.
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