What is the primary oxidation state of manganese in KMnO4?
Practice Questions
Q1
What is the primary oxidation state of manganese in KMnO4?
+2
+4
+6
+7
Questions & Step-by-Step Solutions
What is the primary oxidation state of manganese in KMnO4?
Step 1: Identify the chemical formula KMnO4. It consists of potassium (K), manganese (Mn), and four oxygen (O) atoms.
Step 2: Know the common oxidation states of the elements involved. Potassium (K) has an oxidation state of +1, and oxygen (O) typically has an oxidation state of -2.
Step 3: Calculate the total oxidation state contributed by the four oxygen atoms. Since each oxygen is -2, for four oxygen atoms, it is 4 * (-2) = -8.
Step 4: Set up the equation for the total oxidation states in the compound. The sum of the oxidation states must equal 0 because KMnO4 is neutral.
Step 5: Write the equation: +1 (from K) + x (oxidation state of Mn) + (-8) (from O) = 0.
Step 6: Simplify the equation: +1 + x - 8 = 0, which simplifies to x - 7 = 0.
Step 7: Solve for x: x = +7. This means the oxidation state of manganese (Mn) in KMnO4 is +7.
