A jar contains 5 green, 7 yellow, and 8 blue marbles. If one marble is drawn at
Practice Questions
Q1
A jar contains 5 green, 7 yellow, and 8 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
1/3
5/20
12/20
1/2
Questions & Step-by-Step Solutions
A jar contains 5 green, 7 yellow, and 8 blue marbles. If one marble is drawn at random, what is the probability that it is either green or yellow?
Step 1: Count the number of green marbles in the jar. There are 5 green marbles.
Step 2: Count the number of yellow marbles in the jar. There are 7 yellow marbles.
Step 3: Count the number of blue marbles in the jar. There are 8 blue marbles.
Step 4: Add the total number of marbles together: 5 (green) + 7 (yellow) + 8 (blue) = 20 total marbles.
Step 5: Add the number of green and yellow marbles together: 5 (green) + 7 (yellow) = 12 marbles that are either green or yellow.
Step 6: To find the probability of drawing a green or yellow marble, divide the number of green or yellow marbles (12) by the total number of marbles (20): 12/20.
Step 7: Simplify the fraction 12/20 to its lowest terms: 12/20 = 3/5.
Probability – The likelihood of an event occurring, calculated as the number of favorable outcomes divided by the total number of possible outcomes.
Counting Outcomes – Understanding how to count the total number of items and the number of items that meet certain criteria.
