A bag contains 4 white, 3 black, and 5 red balls. If one ball is drawn at random

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Question: A bag contains 4 white, 3 black, and 5 red balls. If one ball is drawn at random, what is the probability that it is not black?

Options:

Correct Answer: 3/4

Solution:

Total balls = 4 + 3 + 5 = 12. Non-black balls = 4 + 5 = 9. Probability = Non-black balls / Total balls = 9/12 = 3/4.

A bag contains 4 white, 3 black, and 5 red balls. If one ball is drawn at random, what is the probability that it is not black?

A bag contains 4 white, 3 black, and 5 red balls. If one ball is drawn at random, what is the probability that it is not black?

Step 1: Count the number of white balls in the bag. There are 4 white balls.
Step 2: Count the number of black balls in the bag. There are 3 black balls.
Step 3: Count the number of red balls in the bag. There are 5 red balls.
Step 4: Add the total number of balls together: 4 (white) + 3 (black) + 5 (red) = 12 total balls.
Step 5: Count the number of non-black balls. This includes white and red balls: 4 (white) + 5 (red) = 9 non-black balls.
Step 6: To find the probability of drawing a non-black ball, divide the number of non-black balls by the total number of balls: 9 (non-black) / 12 (total) = 3/4.
Step 7: The final answer is that the probability of drawing a ball that is not black is 3/4.

Probability – The likelihood of an event occurring, calculated as the ratio of favorable outcomes to total outcomes.
Counting Principles – Understanding how to count total and favorable outcomes correctly.