In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω),

₹0.0

Question: In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?

Options:

Correct Answer: 2A

Solution:

Total resistance R_total = R1 + R2 = 8Ω + 16Ω = 24Ω. The current is I = V/R_total = 24V / 24Ω = 1A.

In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?

In a circuit with a 24V battery and two resistors in series (R1 = 8Ω, R2 = 16Ω), what is the current flowing through the circuit?

Correct Answer: 1A

Step 1: Identify the values given in the problem. We have a battery voltage of 24V and two resistors: R1 = 8Ω and R2 = 16Ω.
Step 2: Calculate the total resistance in the circuit. Since the resistors are in series, we add them together: R_total = R1 + R2 = 8Ω + 16Ω.
Step 3: Perform the addition: R_total = 8 + 16 = 24Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that I (current) = V (voltage) / R (resistance).
Step 5: Substitute the values into the formula: I = 24V / 24Ω.
Step 6: Perform the division: I = 1A.
Step 7: Conclude that the current flowing through the circuit is 1A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as I = V/R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.