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In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω),

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Question: In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?

Options:

  1. 4V
  2. 6V
  3. 8V
  4. 12V

Correct Answer: 8V

Solution: 

The total resistance is R_total = R1 + R2 = 4Ω + 8Ω = 12Ω. The current is I = V/R_total = 12V / 12Ω = 1A. The voltage across R2 is V_R2 = I * R2 = 1A * 8Ω = 8V.

In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω),

Practice Questions

Q1
In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?
  1. 4V
  2. 6V
  3. 8V
  4. 12V

Questions & Step-by-Step Solutions

In a circuit with a 12V battery and two resistors in series (R1 = 4Ω, R2 = 8Ω), what is the voltage across R2?
Correct Answer: 8V
  • Step 1: Identify the values given in the problem. We have a 12V battery, R1 = 4Ω, and R2 = 8Ω.
  • Step 2: Calculate the total resistance in the circuit. Since the resistors are in series, add R1 and R2 together: R_total = R1 + R2 = 4Ω + 8Ω.
  • Step 3: Calculate the total resistance: R_total = 4Ω + 8Ω = 12Ω.
  • Step 4: Use Ohm's Law to find the current in the circuit. Ohm's Law states that I = V / R. Here, V is the total voltage (12V) and R is the total resistance (12Ω). So, I = 12V / 12Ω.
  • Step 5: Calculate the current: I = 12V / 12Ω = 1A.
  • Step 6: Now, find the voltage across R2 using Ohm's Law again. The formula is V_R2 = I * R2. We already found I = 1A and R2 = 8Ω.
  • Step 7: Calculate the voltage across R2: V_R2 = 1A * 8Ω = 8V.
  • Ohm's Law – Understanding the relationship between voltage, current, and resistance in electrical circuits.
  • Series Circuits – Recognizing how resistors in series affect total resistance and voltage distribution.
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