What is the equivalent capacitance of two capacitors in series, C1 = 6μF and C2

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Question: What is the equivalent capacitance of two capacitors in series, C1 = 6μF and C2 = 3μF?

Options:

Correct Answer: 2μF

Solution:

The formula for equivalent capacitance in series is 1/C_eq = 1/C1 + 1/C2. Thus, 1/C_eq = 1/6 + 1/3 = 1/2, so C_eq = 2μF.

What is the equivalent capacitance of two capacitors in series, C1 = 6μF and C2 = 3μF?

What is the equivalent capacitance of two capacitors in series, C1 = 6μF and C2 = 3μF?

Step 1: Identify the values of the capacitors. Here, C1 = 6μF and C2 = 3μF.
Step 2: Write down the formula for equivalent capacitance in series: 1/C_eq = 1/C1 + 1/C2.
Step 3: Substitute the values of C1 and C2 into the formula: 1/C_eq = 1/6 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
Step 5: Rewrite 1/3 as 2/6, so now we have: 1/C_eq = 1/6 + 2/6.
Step 6: Add the fractions: 1/C_eq = (1 + 2)/6 = 3/6.
Step 7: Simplify 3/6 to 1/2, so now we have: 1/C_eq = 1/2.
Step 8: To find C_eq, take the reciprocal of 1/2: C_eq = 2μF.

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