If a mixture contains 40% alcohol and 60% water, how much alcohol is present in

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Question: If a mixture contains 40% alcohol and 60% water, how much alcohol is present in 15 liters of the mixture?

Options:

Correct Answer: 6 liters

Solution:

40% of 15 liters = 0.4 * 15 = 6 liters of alcohol.

If a mixture contains 40% alcohol and 60% water, how much alcohol is present in 15 liters of the mixture?

If a mixture contains 40% alcohol and 60% water, how much alcohol is present in 15 liters of the mixture?

Step 1: Understand that the mixture is made up of 40% alcohol and 60% water.
Step 2: Identify the total amount of the mixture, which is 15 liters.
Step 3: To find out how much alcohol is in the mixture, calculate 40% of 15 liters.
Step 4: Convert 40% to a decimal. 40% is the same as 0.4.
Step 5: Multiply 0.4 by 15 liters to find the amount of alcohol: 0.4 * 15 = 6 liters.
Step 6: Conclude that there are 6 liters of alcohol in the 15 liters of mixture.

Percentage Calculation – Understanding how to calculate a percentage of a total quantity.
Mixture Composition – Recognizing the components of a mixture and their respective proportions.