What is the total current in a circuit with a 12V battery and three resistors (4

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Question: What is the total current in a circuit with a 12V battery and three resistors (4Ω, 6Ω, and 12Ω) in series?

Options:

Correct Answer: 1 A

Solution:

Total resistance R = 4Ω + 6Ω + 12Ω = 22Ω. Using Ohm\'s Law, I = V / R = 12V / 22Ω ≈ 0.545 A.

What is the total current in a circuit with a 12V battery and three resistors (4Ω, 6Ω, and 12Ω) in series?

What is the total current in a circuit with a 12V battery and three resistors (4Ω, 6Ω, and 12Ω) in series?

Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the resistors in the circuit, which are 4Ω, 6Ω, and 12Ω.
Step 3: Calculate the total resistance by adding the resistances together: 4Ω + 6Ω + 12Ω.
Step 4: Perform the addition: 4 + 6 = 10, then 10 + 12 = 22Ω.
Step 5: Use Ohm's Law to find the current. Ohm's Law states I = V / R.
Step 6: Substitute the values into the formula: I = 12V / 22Ω.
Step 7: Perform the division: 12 divided by 22 is approximately 0.545.
Step 8: Conclude that the total current in the circuit is approximately 0.545 A.

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