What is the Thevenin equivalent voltage across a load resistor in a simple circu
Practice Questions
Q1
What is the Thevenin equivalent voltage across a load resistor in a simple circuit with a 12 V source and a 4 ohm resistor in series with a 2 ohm load?
12 V
8 V
6 V
4 V
Questions & Step-by-Step Solutions
What is the Thevenin equivalent voltage across a load resistor in a simple circuit with a 12 V source and a 4 ohm resistor in series with a 2 ohm load?
Step 1: Identify the components in the circuit. We have a 12 V voltage source, a 4 ohm resistor (R_series), and a 2 ohm load resistor (R_load).
Step 2: Understand that we need to find the voltage across the load resistor (V_load).
Step 3: Use the voltage division formula, which is V_load = V_source * (R_load / (R_series + R_load)).
Step 4: Substitute the values into the formula: V_load = 12 V * (2 ohm / (4 ohm + 2 ohm)).
Step 5: Calculate the total resistance in the denominator: 4 ohm + 2 ohm = 6 ohm.
Step 6: Now substitute this back into the formula: V_load = 12 V * (2 ohm / 6 ohm).
Step 7: Simplify the fraction: 2 / 6 = 1 / 3.
Step 8: Now calculate V_load: V_load = 12 V * (1 / 3) = 4 V.
Step 9: Therefore, the Thevenin equivalent voltage across the load resistor is 4 V.
