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What is the Thevenin equivalent voltage across a load resistor in a simple circu

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Question: What is the Thevenin equivalent voltage across a load resistor in a simple circuit with a 12 V source and a 4 ohm resistor in series with a 2 ohm load?

Options:

  1. 12 V
  2. 8 V
  3. 6 V
  4. 4 V

Correct Answer: 8 V

Solution:

The Thevenin equivalent voltage is the voltage across the load resistor, which can be found using voltage division: V_load = V_source * (R_load / (R_series + R_load)) = 12 V * (2 / (4 + 2)) = 8 V.

What is the Thevenin equivalent voltage across a load resistor in a simple circu

Practice Questions

Q1
What is the Thevenin equivalent voltage across a load resistor in a simple circuit with a 12 V source and a 4 ohm resistor in series with a 2 ohm load?
  1. 12 V
  2. 8 V
  3. 6 V
  4. 4 V

Questions & Step-by-Step Solutions

What is the Thevenin equivalent voltage across a load resistor in a simple circuit with a 12 V source and a 4 ohm resistor in series with a 2 ohm load?
  • Step 1: Identify the components in the circuit. We have a 12 V voltage source, a 4 ohm resistor (R_series), and a 2 ohm load resistor (R_load).
  • Step 2: Understand that we need to find the voltage across the load resistor (V_load).
  • Step 3: Use the voltage division formula, which is V_load = V_source * (R_load / (R_series + R_load)).
  • Step 4: Substitute the values into the formula: V_load = 12 V * (2 ohm / (4 ohm + 2 ohm)).
  • Step 5: Calculate the total resistance in the denominator: 4 ohm + 2 ohm = 6 ohm.
  • Step 6: Now substitute this back into the formula: V_load = 12 V * (2 ohm / 6 ohm).
  • Step 7: Simplify the fraction: 2 / 6 = 1 / 3.
  • Step 8: Now calculate V_load: V_load = 12 V * (1 / 3) = 4 V.
  • Step 9: Therefore, the Thevenin equivalent voltage across the load resistor is 4 V.
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