In a chess tournament, if each player plays against every other player exactly o

In a chess tournament, if each player plays against every other player exactly once, and there are 10 players, how many games are played?

In a chess tournament, if each player plays against every other player exactly once, and there are 10 players, how many games are played?

Step 1: Understand that each player plays against every other player exactly once.
Step 2: Recognize that if there are 10 players, we need to find out how many unique pairs of players can be formed.
Step 3: Use the combination formula to calculate the number of unique pairs. The formula is n(n-1)/2, where n is the number of players.
Step 4: Substitute the number of players (10) into the formula: 10(10-1)/2.
Step 5: Calculate 10-1, which equals 9.
Step 6: Multiply 10 by 9, which equals 90.
Step 7: Divide 90 by 2, which equals 45.
Step 8: Conclude that there are 45 games played in total.

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