What is the Thevenin equivalent resistance seen by the load in a circuit with tw

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Question: What is the Thevenin equivalent resistance seen by the load in a circuit with two resistors (4Ω and 6Ω) in series?

Options:

Correct Answer: 10Ω

Solution:

Rth = R1 + R2 = 4Ω + 6Ω = 10Ω.

What is the Thevenin equivalent resistance seen by the load in a circuit with two resistors (4Ω and 6Ω) in series?

What is the Thevenin equivalent resistance seen by the load in a circuit with two resistors (4Ω and 6Ω) in series?

Step 1: Identify the resistors in the circuit. In this case, we have two resistors: one is 4Ω and the other is 6Ω.
Step 2: Understand that when resistors are in series, the total or equivalent resistance (Rth) is the sum of the individual resistances.
Step 3: Write the formula for the total resistance in series: Rth = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: Rth = 4Ω + 6Ω.
Step 5: Perform the addition: 4Ω + 6Ω = 10Ω.
Step 6: Conclude that the Thevenin equivalent resistance seen by the load is 10Ω.

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