In a series circuit with a 24V source and two resistors of 4Ω and 8Ω, what is th

₹0.0

Question: In a series circuit with a 24V source and two resistors of 4Ω and 8Ω, what is the voltage across the 8Ω resistor?

Options:

Correct Answer: 16V

Solution:

Using voltage division, V8Ω = Vtotal * (R8Ω / (R4Ω + R8Ω)) = 24V * (8Ω / (4Ω + 8Ω)) = 24V * (8/12) = 16V.

In a series circuit with a 24V source and two resistors of 4Ω and 8Ω, what is the voltage across the 8Ω resistor?

In a series circuit with a 24V source and two resistors of 4Ω and 8Ω, what is the voltage across the 8Ω resistor?

Step 1: Identify the total voltage in the circuit, which is given as 24V.
Step 2: Identify the resistors in the circuit. We have R1 = 4Ω and R2 = 8Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors: Rtotal = R1 + R2 = 4Ω + 8Ω = 12Ω.
Step 4: Use the voltage division formula to find the voltage across the 8Ω resistor: V8Ω = Vtotal * (R8Ω / Rtotal).
Step 5: Substitute the values into the formula: V8Ω = 24V * (8Ω / 12Ω).
Step 6: Simplify the fraction: 8Ω / 12Ω = 2/3.
Step 7: Multiply 24V by 2/3 to find V8Ω: V8Ω = 24V * (2/3) = 16V.

Voltage Division – The principle that in a series circuit, the voltage across a resistor is proportional to its resistance relative to the total resistance.
Series Circuit – A circuit configuration where components are connected end-to-end, resulting in the same current flowing through each component.
Ohm's Law – The relationship between voltage, current, and resistance, expressed as V = IR.