In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A
Practice Questions
Q1
In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A and the Norton resistance (Rn) is 5Ω, what is the Norton equivalent voltage (Vn)?
15V
10V
5V
3V
Questions & Step-by-Step Solutions
In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A and the Norton resistance (Rn) is 5Ω, what is the Norton equivalent voltage (Vn)?
Step 1: Identify the short-circuit current (Isc) given in the problem, which is 3A.
Step 2: Identify the Norton resistance (Rn) given in the problem, which is 5Ω.
Step 3: Use Ohm's law to find the Norton equivalent voltage (Vn). The formula is Vn = Isc * Rn.
Step 4: Substitute the values into the formula: Vn = 3A * 5Ω.
