In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A

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Question: In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A and the Norton resistance (Rn) is 5Ω, what is the Norton equivalent voltage (Vn)?

Options:

Correct Answer: 15V

Solution:

Norton voltage can be calculated using Ohm\'s law: Vn = Isc * Rn = 3A * 5Ω = 15V.

In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A

Practice Questions

In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A and the Norton resistance (Rn) is 5Ω, what is the Norton equivalent voltage (Vn)?

Questions & Step-by-Step Solutions

In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A and the Norton resistance (Rn) is 5Ω, what is the Norton equivalent voltage (Vn)?

Step 1: Identify the short-circuit current (Isc) given in the problem, which is 3A.
Step 2: Identify the Norton resistance (Rn) given in the problem, which is 5Ω.
Step 3: Use Ohm's law to find the Norton equivalent voltage (Vn). The formula is Vn = Isc * Rn.
Step 4: Substitute the values into the formula: Vn = 3A * 5Ω.
Step 5: Calculate the result: Vn = 15V.

Norton Equivalent Circuit – A representation of a complex circuit as a current source in parallel with a resistor.
Ohm's Law – A fundamental principle stating that voltage (V) is the product of current (I) and resistance (R), expressed as V = I * R.

In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A

What’s inside this PDF?

In a circuit with a Norton equivalent, if the short-circuit current (Isc) is 3A

Practice Questions

Questions & Step-by-Step Solutions

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